n05tr4d4177u5
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Can someone tell me what is the integral of
(-39240)(9-x^2)^(1/2)
(-39240)(9-x^2)^(1/2)
The integral of the function (-39240)(9-x^2)^(1/2) is expressed as ∫ -39240√(9-x²)dx. To solve this integral, the method of trigonometric substitution is required, specifically substituting x with 3sin(θ) to simplify the square root. This approach allows for the integration of the resulting trigonometric function, leading to a solution that can be expressed in terms of θ.
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