Find the Integral of (-39240)(9-x^2)^(1/2) with Easy Step-by-Step Guide

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SUMMARY

The integral of the function (-39240)(9-x^2)^(1/2) is expressed as ∫ -39240√(9-x²)dx. To solve this integral, the method of trigonometric substitution is required, specifically substituting x with 3sin(θ) to simplify the square root. This approach allows for the integration of the resulting trigonometric function, leading to a solution that can be expressed in terms of θ.

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Can someone tell me what is the integral of

(-39240)(9-x^2)^(1/2)
 
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rewritten

-39240 times the square root of (9 - x squared)
 
Alrighty. We have \int -39240\sqrt{9-x^2}dx

This is going to use trig substitution. Any ideas?
 

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