Find the Inverse of a Function | Step-by-Step Guide & Examples

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SUMMARY

The discussion focuses on finding the inverse of the function y = (x - 1) / (x - 2). The user, Dan, initially misinterprets the solution but later realizes that the answer provided, y = (1 - 2x) / (1 - x), is equivalent to his derived expression y = (2x - 1) / (x - 1). This highlights the importance of recognizing equivalent forms of functions when solving for inverses.

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Students learning algebra, educators teaching function inverses, and anyone looking to improve their skills in algebraic manipulation and function analysis.

danago
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Hi. The question wants me to find the inverse of [tex] y = \frac{{x - 1}}{{x - 2}}[/tex]

Heres my working for it:
[tex] \begin{array}{l}<br /> x = \frac{{y - 1}}{{y - 2}} \\ <br /> xy - 2x = y - 1 \\ <br /> xy - y = 2x - 1 \\ <br /> (x - 1)y = 2x - 1 \\ <br /> y = \frac{{2x - 1}}{{x - 1}} \\ <br /> \end{array}[/tex]

The answer says something different though.

If anybody could please tell me where I am going wrong, or perhaps if the answer book is wrong, id greatly appreciate it.

Thanks,
Dan.
 
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Ahh nevermind sorry.

My stupid mistake. The answer said [tex] y = \frac{{1 - 2x}}{{1 - x}}[/tex] which i just realized is exactly the same thing.

Thanks anyway :)
 

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