Find the limit of (sqrt(1+x) - 1)/(cuberoot(1+x)-1) as x->0

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Homework Help Overview

The discussion revolves around finding the limit of the expression (sqrt(1+x) - 1)/(cuberoot(1+x)-1) as x approaches 0, which involves concepts from calculus related to limits and potentially Taylor series or rationalization techniques.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts a change of variables to simplify the limit but encounters difficulties. Some participants suggest using Taylor series, while others propose rationalizing the denominator as a method to simplify the expression further.

Discussion Status

The discussion is ongoing, with participants exploring different methods to approach the limit. Some guidance has been provided regarding rationalization and variable substitution, but there is no explicit consensus on the final outcome or correctness of the calculations presented.

Contextual Notes

There is an emphasis on changing variables and rationalizing the denominator, with some participants expressing a preference for these methods over others like Taylor series. The calculations leading to the limit have not been fully detailed, leaving room for further exploration and verification.

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Find the limit of (sqrt(1+x) - 1)/(cuberoot(1+x)-1) as x-->0

Homework Statement



Fin limit of the follwing as x tends to 0:

[sqrt(1+x)-1]/[cuberoot(1+x)-1]

Homework Equations





The Attempt at a Solution



using change of variables:
let y=sqrt(1+x)
so = limit (as y tends to 1): [y-1]/cuberoot(y^2)-1]

Then i got stuck.

any help woyld be v much appreciated.
Thank you.
 
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have you done taylor series?
 


Yes but we have to do this by changing the variables.
 


Looks to me like a problem where you would want to "rationalize the denominator.
[itex]a^3- b^3= (a- b)(a^2+ ab+ b^2)[/itex] so to "rationalize" [itex]^3\sqrt{y^2}- 1[/itex], you need to multiply by [itex]^3\sqrt{y^4}+ ^3\sqrt{y^2}+ 1[/itex]. Multiplying the numerator and denominator by that will make the denominator [itex]y^2- 1[/itex]. You should be able to factor a "y- 1" out of the numerator also to cancel the "y- 1" in the denominator,.
 
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Ok so after i cancel the y-1, i get:
(cuberoot(y^2)+1)/(y+1)
so substituting the y=1, i should get limit =1
is that right?
 


Assuming you the calculations correctly, which you did not show, yes.
 


since after cancelling the y-1,this will give: (cuberoot(y^2)+1)/(y+1)=2/2=1

Thank you.
 

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