Find the partial derivatives of the function

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SUMMARY

The discussion focuses on finding the partial derivatives of the function f(x,y) = -(-7x - 2y) / (9x + 7y). The correct calculations for the partial derivatives are fx(x,y) = (-7 - 2y) / (9 + 7y) and fy(x,y) = (-7x - 2) / (9x + 7). Participants confirm the use of the quotient rule for differentiation as the appropriate method for handling the function's fractional form.

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  • Understanding of partial derivatives
  • Familiarity with the quotient rule in calculus
  • Basic knowledge of functions of multiple variables
  • Proficiency in algebraic manipulation of fractions
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Students in calculus courses, mathematics enthusiasts, and anyone seeking to understand the process of finding partial derivatives in multivariable functions.

cwesto
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The problem:
f(x,y)=-[tex]\frac{-7x-2y}{9x+7y}[/tex]

find:

fx(x,y)
fy(x,y)

The attempt:

fx(x,y)=[tex]\frac{-7-2y}{9+7y}[/tex]
fy(x,y)=[tex]\frac{-7x-2}{9x+7}[/tex]

Questions:

I'm not exactly sure how to find the partail derivative with a fraction like this one.
 
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use the quotient rule for differentiation? or product rule but with (9+7y)^(-1) for eg.

is this homework? it looks like the wrong forum to me
 
Oh sorry.
 

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