MHB Find the Slope of a Curve y=f(x) at (a,f(a)) - Determine a f

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The discussion focuses on finding the slope of the curve y=f(x) at the point (a, f(a)) using limits. One participant initially calculated the limit incorrectly, arriving at 144, while another correctly simplified the expression and found the limit to be 48. The confusion arose from the handling of the constant term 72 during simplification. Participants emphasized the importance of careful algebraic manipulation to avoid errors. The conversation highlights the need for practice in calculus to master these concepts.
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The limit below represents the slope of a curve y=​f(x) at the point​ (a,f(a)). Determine a​ f

View attachment 6113After finding the f(x) and a, I did this:8(3^2+3h(3)+3h(3)+h^2)-72 dividing by h

getting h(8h^2+144) dividing by h; canceling the h's

and the plugging in the limit h --> 0 getting 144. But I am getting it wrong.

What is the issue?
 

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Re: The limit below represents the slope of a curve y=​f(x) at the point​ (a,f(a)). Determine a​ f

$$\frac{8(3+h)^2-72}{h}=\frac{8(9+6h+h^2-9)}{h}=\frac{8h(6+h)}{h}=8(6+h)$$

Then as $h\to0$, the limit is 48. :)
 
Re: The limit below represents the slope of a curve y=​f(x) at the point​ (a,f(a)). Determine a​ f

MarkFL said:
$$\frac{8(3+h)^2-72}{h}=\frac{8(9+6h+h^2-9)}{h}=\frac{8h(6+h)}{h}=8(6+h)$$

Then as $h\to0$, the limit is 48. :)

What! cmon...ahhhh okay dang it need more math pratice XD...what happen to 72?
 

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