Find which nitrate has the lowest pH

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SUMMARY

The discussion centers on determining which nitrate compound has the lowest pH among five options: Mg(NO3)2, Ca(NO3)2, Al(NO3)3, KNO3, and Zn(NO3)2. The consensus concludes that Al(NO3)3 has the lowest pH due to the +3 charge of aluminum, which bonds with three hydroxide ions, resulting in a higher concentration of hydrogen ions. This contrasts with KNO3, which only bonds with one hydroxide ion, leading to a higher pH. Participants emphasized the importance of understanding the Brønsted-Lowry theory of acids and bases in this context.

PREREQUISITES
  • Understanding of Brønsted-Lowry theory of acids and bases
  • Knowledge of dissociation of ionic compounds in water
  • Familiarity with the concept of oxidation states
  • Basic chemistry principles regarding pH and hydroxide ions
NEXT STEPS
  • Research the dissociation of metal nitrates in aqueous solutions
  • Study the relationship between oxidation states and acidity
  • Explore equilibrium reactions and their implications in acid-base chemistry
  • Consult solubility and stability constant tables for various metal hydroxides
USEFUL FOR

Chemistry students, educators, and anyone interested in understanding acid-base reactions and the behavior of metal nitrates in solution.

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Homework Statement



Which solution will have the lowest pH?
a) Mg(NO3)2
b) Ca(NO3)2
c) Al(NO3)3
d) KNO3
e) Zn(NO3)2

Homework Equations



None I know of.

The Attempt at a Solution



My reasoning was that when the metal dissociates from the nitrate, it will leave a negative charge on the nitrate. I need to find which one will have the lowest pH, so I figured that the KNO3 would dissociate and leave the NO3 with 1 negative charge, which would only attract 1 hydrogen ion, leaving the least amount of OH ions, meaning the solution would have a lower pH than the other ones, since they would dissociate and attract more hydrogens, leaving more OH ions, which would cause the pH to be higher.
But apparently that's not the case.

So I'm stumped. Please help.
 
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Men+ + mH2O <=> Me(OH)m(n-m)+ + mH+
 
Borek said:
Men+ + mH2O <=> Me(OH)m(n-m)+ + mH+

I don't understand.
 
leroyjenkens said:
I don't understand.

Borek wanted to convey that the metal ions would form hydroxides through reaction with water.

The metal ion which would use more OH- will result in increased concentration of H+. (H2O <=> OH-+H+)
 
See which one gives,more
H3O+
H+

Lowest pH means acids
 
I learned weeks ago, that you can find it by oxidation number. If I remember clearly below number the metal has, it's acid
 
Is the the answer KNO3?
 
Bandarigoda said:
I learned weeks ago, that you can find it by oxidation number. If I remember clearly below number the metal has, it's acid

No.

Bandarigoda said:
Is the the answer KNO3?

No.
 
Borek said:
No.
No.

As usually I suck at chemistry. Could u explain more easy way to determine it? Sorry for my English
 
  • #11
Pranav-Arora said:
Borek wanted to convey that the metal ions would form hydroxides through reaction with water.

The metal ion which would use more OH- will result in increased concentration of H+. (H2O <=> OH-+H+)

Oh, I was confused what Me and m were for. I guess m was just used as a variable and Me stands for metal.

So the opposite of what I thought was true. When the Al(NO3)3 dissociates, that leaves an Al with a +3 charge, which will bond to 3 OH, which will leave 3 H cations. For the one I chose, K will only bond to 1 OH, leaving just 1 H cation, which will have a higher pH. So the lowest pH will be the Al(NO3)3.

Thanks guys.
 
  • #12
leroyjenkens said:
Oh, I was confused what Me and m were for. I guess m was just used as a variable and Me stands for metal.

Yes, Me is a metal, and m, n are just some integeres.

So the opposite of what I thought was true. When the Al(NO3)3 dissociates, that leaves an Al with a +3 charge, which will bond to 3 OH, which will leave 3 H cations. For the one I chose, K will only bond to 1 OH, leaving just 1 H cation, which will have a higher pH. So the lowest pH will be the Al(NO3)3.

Beware - these are all equilibrium reactions. It doesn't mean these reactions proceed to an end, so your conclusion is not necessarily correct. TBH without consulting solubility/stability constant tables I am not sure what is the correct answer here.
 

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