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2.2 m/s^2 for 5.9 s. Find the net work done on the box

m=6.0kg

a=2.2m/s^2

t=5.9 s

a=0 degrees

i know W=Fdcos(a)

and F=ma

so,

F=6.0kg*2.2m/s^2=13.2N

W=13.2N*d*cos0=13.2N*d

I am a little unsure as how to find d though. would it be one of the kinematic equations?