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Find work done given time, acceleration, and mass

  1. Oct 18, 2010 #1
    a box with a mass of 6.0 kg is accelerated from rest by a force across a floor at a rate of
    2.2 m/s^2 for 5.9 s. Find the net work done on the box

    t=5.9 s
    a=0 degrees

    i know W=Fdcos(a)
    and F=ma


    I am a little unsure as how to find d though. would it be one of the kinematic equations?
    1. The problem statement, all variables and given/known data

    2. Relevant equations

    3. The attempt at a solution
  2. jcsd
  3. Oct 18, 2010 #2


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    hi daltomagne! :smile:

    (try using the X2 icon just above the Reply box :wink:)
    That's right. :smile:

    You can either use one of the standard constant acceleration equations to find d, or you can use another of them to find vf, and then apply the work-energy theorem ( work done = change in mechanical energy).
  4. Oct 18, 2010 #3
    so i'm thinking v=vi+at and that gives me vi=-12.98m/s
    but that gives me a value for x=-38.3 m?

    so something isn't adding up
  5. Oct 18, 2010 #4


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    where's the contradiction? :confused:

    one figure is speed, the other is distance, they should both give you the same work. :wink:
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