MHB Find x_1+x_3+x_5+--------+x_999

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The problem involves a sequence of equations where each pair of consecutive variables sums to 1, and the total sum of all variables from x_1 to x_999 equals 999. Given that there are 999 variables, the equations imply that each variable can be expressed in terms of its neighbors. The task is to find the sum of the odd-indexed variables, specifically x_1, x_3, x_5, and so on, up to x_999. The solution requires recognizing the pattern in the sums and applying algebraic manipulation to derive the final result.
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$x_1+x_2=x_2+x_3=x_3+x_4=x_4+x_5=--------=x_{998}+x_{999}=1$

$x_1+x_2+x_3+x_4+x_5+--------+x_{999}=999$

find :

$x_1+x_3+x_5+x_7+---+x_{999}=?$
 
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Albert said:
$x_1+x_2=x_2+x_3=x_3+x_4=x_4+x_5=--------=x_{998}+x_{999}=1$

$x_1+x_2+x_3+x_4+x_5+--------+x_{999}=999$

find :

$x_1+x_3+x_5+x_7+---+x_{999}=?$

Given
$x_1+x_2=x_2+x_3=x_3+x_4=x_4+x_5=\cdots=x_{998}+x_{999}=1\cdots(1)$
$x_1+x_2+x_3+x_4+x_5+\cdots+x_{999}=999\cdots(2)$
we have $x_1+x_2=x_2+x_3$ => $x_1= x_3$ ( from (1)
proceeding this way
$x_1 = x_3 = x_ 5 = \cdots = x_{999}\cdots(3)$
and similarly
$x_2 = x_4 = x_ 6 =\cdots = x_{998}\cdots(4)$
further from given relations
$x_1+ x_2 = 1\cdots(5) $ (from(1)
and $500x_1 + 499x_2 = 999\cdots(6) $ from (2), (3) and (4)
multiply (5) by 499 and subtract from (6) giving
$x_1 = 500$
so $x_1+x_3+x_5+x_7+---+x_{999}=500^2 = 250000$
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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