Finding 2nd Dark Fringe Angle for Diffraction Single Slit 1.5x10^6m

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SUMMARY

The discussion focuses on calculating the angle for the second dark fringe in a single-slit diffraction pattern with a slit width of 1.5 x 10^6 m. The correct formula to use is d sin(θ) = nλ, where n = 2 for the second dark fringe. The wavelengths provided are 425 nm and 650 nm, leading to the angles θ of approximately 16.46 degrees and 25.68 degrees, respectively. The initial answers given were incorrect due to the misinterpretation of the fringe order.

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Laceb04
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A single slit has a width of 1.5 x 10^6 m and is used to form a diffraction pattern. Find the angle that locates the second dark fringe when the wavelength of the light is each of the following.

(a) 425 nm

(b) 650 nm


I answered with (a) 16.46 and (b) 25.68 but these answers are wrong
 
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You're asked for the second dark fringes, which I suppose means n = 2 in the equation
[tex]d \sin\theta = n\lambda[/tex]
(you've apparently used n = 1)
 

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