Finding a direction vector from ax + by + cz + d = 0

[Nevermore]

How would I find the direction vector of a line given in the form ax + by + cz +d =0?

Thankyou.

 

[TD]

I see an equation of a plane, not a line.

 

[Nevermore]

Damn, sorry, got carried away with my letters. I meant ax + by +c = 0. Sorry about that...

 

[TD]

Damn, sorry, got carried away with my letters. I meant ax + by +c = 0. Sorry about that...

For a line, (1,m) is always a directional vector where m is the slope. Can you find the slope?

 

[Nevermore]

Yeah - I thought it would be something simple like that. Thanks for your help.

 

[TD]

You're welcome

 

[SirAllan]

Thanks for asking that Q, it helped me too

 

[Defennder]

I don't think there's a need to thank someone who started a thread two years ago and have not posted since.

 

[SirAllan]

LORL... Thanks for pointing that out. ( At least you still logon)