Finding acceleration in a kinematics problem

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Handwritten physics work on lined paper: a 20 kg block on a table tied by a string over a pulley to a 10 kg block on a 30 degree incline, with MK = .1 and MK = .2 labelled, followed by equations solving for a and tensions T1 and T2, ending with a = 3.68 m/s^2 and a blank white box.


Sorry about bad picture. I did best I could but I am not sure that's how I do this problem.
If I am wrong can you give me right equations for this? Thank you. :)
 
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about a

can you specify which block has acceleration 'a'.
 
i have no clue. That's how my teacher wrote the problem as take home problem. He just had pictures and what is a = ? I think he meant total acceleration. He gave us similar problems few weeks ago but it was on two boxes without mk instead of box and triangle with mk. So I used formula to find acceleration of each blocks and found T1 and T2 and then applied to same formula he used on the problem he did few weeks ago. :(
 
a

a should be 15/4.
(i used g=10 not 9.8)
the acceleration of each block is the same.
 
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explanation

T1=10a
T2-10gsin30=10a
20g-(T1+T2)=20a

solve these to find "a".
 
err.. I can't really tell how your equation works with that 3 short equations. Did you use mk = .1 and mk = .2 on each side to get the answer?
 
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do you know the Newtons second law.
ƩFx=max
ƩFy=may

first draw the free body diagram of each block and then apply these eqns to get my above eqns
 
but you sure it's 15/4 not 15/40? when I plug in my t1 and t2 and solve for a using your 3 line equation, I get 15/40