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Lost_Prophet75
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Homework Statement
A 26.5 kg block is connected to an empty 1.00 kg bucket by a cord running over a frictionless pulley (Fig. 4-57). The coefficient of static friction between the table and the block is 0.435 and the coefficient of kinetic friction between the table and the block is 0.320. Sand is gradually added to the bucket until the system just begins to move.
Homework Equations
So far I have solved the mass of the sand added to the bucket, which is 10.528kg, ignoring the mass of the bucket. I am still unsure of how to setup the equation, because I am confused on what I use for tension. The tension I originally used should have changed due to the mass of the sand now added to the bucket. The first time I solved for tension, I didn't need acceleration, as the bucket was at rest. Every equation I try to set up comes out needing two variables, neither of which I have any idea how to solve for.
The Attempt at a Solution
When I try to find tension, my equation comes out to one of these two (Sorry if I write these wrong, still figuring out how to type out an equation).
For the Tension in the block, i get T=[tex]\mu[/tex]N + ma, which requires the use of either tension or acceleration to solve. I got this equation by using a free-body diagram, which had weight going down the y-axis, normal force going up the y-axis, tension to the right on the x-axis, and Friction going left on the x-axis. The sum of my forces would then be Tension minus friction equals mass times acceleration, so I moved friction over, and converted it to mu times normal force.
My Other equation is for the bucket, which is T=mg +ma. For this one, ny free body has two forces acting on it, both on the y-axis. Tension going up, weight moving it down. My sum of forces came out to be Tension minus weight equals mass times acceleration.
What am I missing here, or am I over complicating things?