A skier travels with a constant speed of 6 m/s along a parabolic path y= x2/20. Find the acceleration of the skier when he is at (10,5). Neglect the size of skier.
dy/dx is slope of parabola.
In a straight line if body has distance covered=x, then velocity (v) = dx/dt and acceleration = dv/dt
Radial acceleration is v2/R where R is radius.
The Attempt at a Solution
Slope is 2x/20= x/10.
For straight line determining acceleration is easy but how about this curve case?