- #1
CCMarie
- 11
- 1
Thread moved from the technical forums, so no Homework Template is shown
I have this problem to solve until tomorrow:
A point moves along the parabola r*cos^2(θ/2) = p/2, p > 0, in the direction that θ increases. At the time t=0, the point is on the verge of the parabola. The velocity is v = k*r, k>0.
What is the equation of movement, the radial acceleration and the transverse acceleration.
I've tried to solve it by rewriting the equation of the parabola r = (-2d)/(1+cosθ), and than I thought about derivation of this equation as both r and theta are functions of t, r(t) and θ(t).
I tried to find the acceleration that is the first derivative of the velocity a = k r'(t). And I wrote the equation of movement as s(t) = 1/2*k*t^2*r'(t).
I don't know if what I did so far is ok. And I am not quite sure how to work with the radial and transverse acceleration.
I would really appreciate some clues. Thank you.
A point moves along the parabola r*cos^2(θ/2) = p/2, p > 0, in the direction that θ increases. At the time t=0, the point is on the verge of the parabola. The velocity is v = k*r, k>0.
What is the equation of movement, the radial acceleration and the transverse acceleration.
I've tried to solve it by rewriting the equation of the parabola r = (-2d)/(1+cosθ), and than I thought about derivation of this equation as both r and theta are functions of t, r(t) and θ(t).
I tried to find the acceleration that is the first derivative of the velocity a = k r'(t). And I wrote the equation of movement as s(t) = 1/2*k*t^2*r'(t).
I don't know if what I did so far is ok. And I am not quite sure how to work with the radial and transverse acceleration.
I would really appreciate some clues. Thank you.