- #1

CCMarie

- 11

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Thread moved from the technical forums, so no Homework Template is shown

I have this problem to solve until tomorrow:

A point moves along the parabola r*cos^2(θ/2) = p/2, p > 0, in the direction that θ increases. At the time t=0, the point is on the verge of the parabola. The velocity is v = k*r, k>0.

What is the equation of movement, the radial acceleration and the transverse acceleration.

I've tried to solve it by rewriting the equation of the parabola r = (-2d)/(1+cosθ), and than I thought about derivation of this equation as both r and theta are functions of t, r(t) and θ(t).

I tried to find the acceleration that is the first derivative of the velocity a = k r'(t). And I wrote the equation of movement as s(t) = 1/2*k*t^2*r'(t).

I don't know if what I did so far is ok. And I am not quite sure how to work with the radial and transverse acceleration.

I would really appreciate some clues. Thank you.

A point moves along the parabola r*cos^2(θ/2) = p/2, p > 0, in the direction that θ increases. At the time t=0, the point is on the verge of the parabola. The velocity is v = k*r, k>0.

What is the equation of movement, the radial acceleration and the transverse acceleration.

I've tried to solve it by rewriting the equation of the parabola r = (-2d)/(1+cosθ), and than I thought about derivation of this equation as both r and theta are functions of t, r(t) and θ(t).

I tried to find the acceleration that is the first derivative of the velocity a = k r'(t). And I wrote the equation of movement as s(t) = 1/2*k*t^2*r'(t).

I don't know if what I did so far is ok. And I am not quite sure how to work with the radial and transverse acceleration.

I would really appreciate some clues. Thank you.