A 593 N physics student stands on a bathroom scale in an 875 kg (including the student) elevator that is supported by a cable. As the elevator starts moving, the scale reads 424 N.
A. Find the magnitude of the acceleration of the elevator.
B. What is the acceleration if the scale reads 639 N?
C. What is the tension in the cable in part A?
D. What is the tension in the cable in part B?
ƩF = ma
T= ma +mg
The Attempt at a Solution
A. 424-593 =60.5a
-2.79 = a
B. 639-593= 60.5a
0.76 = a
C. (875)(2.79)+(593) =T
3034 N = T
D. (875)(.76) + 593
1259 N = T
Is this right? Thanks.
Also, would acceleration stay negative for part C?