- #1
DaalChawal
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Doubt in marked step(Numerator) that how it came from first?
Is there any alternative solution for this?
MHB Finding an Alternative Solution to Doubtful Numerator Steps
- Thread starter DaalChawal
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The discussion centers on addressing doubts regarding the derivation of a specific numerator step in a mathematical context. Participants explore whether there are alternative solutions to the problem posed, particularly in relation to the identity $\sin^2x + \cos^2 x=1$. An alternative formulation using complex numbers, $\sin^2x - i^2 \cos^2 x=1$, is suggested for further exploration. The substitution of $x=\frac{2\pi}{9}$ is proposed as a specific case to investigate. Overall, the thread seeks clarity on the validity of these steps and potential solutions.
Doubt in marked step(Numerator) that how it came from first?
Is there any alternative solution for this?
- #2
I like Serena
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MHB
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We generally have $\sin^2x + \cos^2 x=1$.
So $\sin^2x - i^2 \cos^2 x=1$ as well.
Now substitute $x=\frac{2\pi}{9}$.
So $\sin^2x - i^2 \cos^2 x=1$ as well.
Now substitute $x=\frac{2\pi}{9}$.
- #3
DaalChawal
- 85
- 0
Thanks
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