DaalChawal
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Doubt in marked step(Numerator) that how it came from first?
Is there any alternative solution for this?
Finding an Alternative Solution to Doubtful Numerator Steps
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Doubt in marked step(Numerator) that how it came from first?
Is there any alternative solution for this?
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We generally have $\sin^2x + \cos^2 x=1$.
So $\sin^2x - i^2 \cos^2 x=1$ as well.
Now substitute $x=\frac{2\pi}{9}$.
So $\sin^2x - i^2 \cos^2 x=1$ as well.
Now substitute $x=\frac{2\pi}{9}$.
DaalChawal
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Thanks