Finding average resistive force

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SUMMARY

The discussion centers on calculating the average resistive force exerted on a 70-kg diver who drops from a 10-meter tower and comes to rest 5 meters beneath the water's surface. The relevant equation for this problem is the conservation of energy equation: (KE + PEg + PEs)i = (KE + PEg + PEs)f. The diver's kinetic energy (KE) upon hitting the water and the work done to stop him are critical components for determining the average resistive force.

PREREQUISITES
  • Understanding of kinetic energy (KE) and potential energy (PEg, PEs)
  • Familiarity with the conservation of energy principle
  • Basic knowledge of work-energy calculations
  • Ability to perform calculations involving gravitational acceleration (9.81 m/s²)
NEXT STEPS
  • Calculate the diver's kinetic energy (KE) just before hitting the water using KE = 0.5 * m * v².
  • Determine the work done to stop the diver using the work-energy principle.
  • Learn how to calculate average resistive force using the formula: F = Work / Distance.
  • Explore the concepts of buoyancy and drag force in fluid dynamics for a deeper understanding.
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in mechanics, particularly in understanding forces acting on objects in fluid environments.

jman1209
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I really need help with this!

Homework Statement


A 70-kg diver steps off a 10-m tower and drops from rest strait down into the water. If he comes to rest 5.0 m beneath the surface, determine the average resistive force exerted on him by the water.

Homework Equations


This is the only equation that I know goes with this problem:
(KE + PEg + PEs)i = (KE + PEg + PEs)f

The Attempt at a Solution


I can't get anywhere with this.
 
Physics news on Phys.org
What's the diver's KE when he hits the water? What's his KE when he comes to a stop? How much work was done stopping him? How do you calculate work?
 

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