Finding Complete Orthogonal Systems for Boundary Value Problems

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SUMMARY

The discussion focuses on finding a complete orthogonal system for boundary value problems involving a $C^{\infty}$ function $f: [0, \pi] \to \mathbb{R}$ with boundary conditions $f(0)=f(\pi)=0$. The participants conclude that the Fourier Series provides the necessary framework, specifically using the sine functions to satisfy the boundary conditions. The orthogonal system derived is $\{ x \mapsto \sin(kx) \mid k \in \mathbb{Z}_{>0} \}$, indicating that the coefficients $a_k$ must be zero due to the boundary conditions.

PREREQUISITES
  • Understanding of Fourier Series and their properties
  • Knowledge of boundary value problems in differential equations
  • Familiarity with $C^{\infty}$ functions and their characteristics
  • Basic concepts of orthogonality in function spaces
NEXT STEPS
  • Study the derivation of Fourier Series coefficients for various functions
  • Explore the application of boundary conditions in solving differential equations
  • Learn about eigenfunctions and their role in orthogonal systems
  • Investigate the implications of initial value problems on Fourier Series solutions
USEFUL FOR

Mathematicians, physicists, and engineers working with boundary value problems, particularly those utilizing Fourier Series for solutions in applied mathematics and theoretical physics.

evinda
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Hello! (Wave)

Suppose that we have a $C^{\infty}$ function $f: [0, \pi] \to \mathbb{R}$ for which it holds that $f(0)=f(\pi)=0$.

How can we find a complete orthogonal system of this space? (Thinking)
 
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evinda said:
Hello! (Wave)

Suppose that we have a $C^{\infty}$ function $f: [0, \pi] \to \mathbb{R}$ for which it holds that $f(0)=f(\pi)=0$.

How can we find a complete orthogonal system of this space? (Thinking)

Hey! (Smile)

Have you considered a Fourier Series? (Wondering)
 
I like Serena said:
Hey! (Smile)

Have you considered a Fourier Series? (Wondering)

So do we find the coefficients of the Fourier series

$$f \sim \frac{a_0}{2}+ \sum_{k=1}^{\infty} ( a_k \cos(kx)+ b_k \sin(kx)) $$

and from this we find an orthogonal system? How can we do it? (Thinking)
 
evinda said:
So do we find the coefficients of the Fourier series

$$f \sim \frac{a_0}{2}+ \sum_{k=1}^{\infty} ( a_k \cos(kx)+ b_k \sin(kx)) $$

and from this we find an orthogonal system? How can we do it? (Thinking)

First off, we know that the Fourier series is an orthogonal system. (Nerd)

Since each function in the system must fit the boundary conditions, it follows that $a_k=0$.
So we're left with:
$$f(x) = \sum_{k=1}^{\infty} b_k \sin(kx)$$
(Thinking)

That is, the orthogonal system is:
$$\{ x \mapsto \sin(kx) \mid k \in \mathbb Z_{>0} \}$$
(Mmm)
 
I like Serena said:
First off, we know that the Fourier series is an orthogonal system. (Nerd)

Since each function in the system must fit the boundary conditions, it follows that $a_k=0$.
So we're left with:
$$f(x) = \sum_{k=1}^{\infty} b_k \sin(kx)$$
(Thinking)

That is, the orthogonal system is:
$$\{ x \mapsto \sin(kx) \mid k \in \mathbb Z_{>0} \}$$
(Mmm)

So the complete orthogonal system is the set of the eigenfunctions, right? (Thinking)
 
evinda said:
So the complete orthogonal system is the set of the eigenfunctions, right? (Thinking)

Which eigenfunctions? :confused:
 
I like Serena said:
Which eigenfunctions? :confused:

Oh, this holds only if we are given an initial value problem, right? (Thinking)

So if we are given a function and boundary conditions, do we find the Fourier series of the function and apply the boundary conditions and the orthogonal complete system will consist of the functions $1$ / $\sin kx$ / $\cos kx$ that will remain? (Thinking)
 
evinda said:
Oh, this holds only if we are given an initial value problem, right? (Thinking)

So if we are given a function and boundary conditions, do we find the Fourier series of the function and apply the boundary conditions and the orthogonal complete system will consist of the functions $1$ / $\sin kx$ / $\cos kx$ that will remain? (Thinking)

Basically, yes. (Smile)
 

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