MHB Finding Complete Orthogonal Systems for Boundary Value Problems

Click For Summary
To find a complete orthogonal system for a $C^{\infty}$ function defined on [0, π] with boundary conditions f(0) = f(π) = 0, the Fourier series approach is suggested. The Fourier series can be expressed as f(x) = ∑ b_k sin(kx), where the cosine terms are eliminated due to the boundary conditions. This leads to the conclusion that the orthogonal system consists of the functions sin(kx) for k in the positive integers. The discussion emphasizes that the complete orthogonal system is derived from the eigenfunctions relevant to the given boundary conditions. Overall, the Fourier series method effectively identifies the orthogonal system needed for boundary value problems.
evinda
Gold Member
MHB
Messages
3,741
Reaction score
0
Hello! (Wave)

Suppose that we have a $C^{\infty}$ function $f: [0, \pi] \to \mathbb{R}$ for which it holds that $f(0)=f(\pi)=0$.

How can we find a complete orthogonal system of this space? (Thinking)
 
Physics news on Phys.org
evinda said:
Hello! (Wave)

Suppose that we have a $C^{\infty}$ function $f: [0, \pi] \to \mathbb{R}$ for which it holds that $f(0)=f(\pi)=0$.

How can we find a complete orthogonal system of this space? (Thinking)

Hey! (Smile)

Have you considered a Fourier Series? (Wondering)
 
I like Serena said:
Hey! (Smile)

Have you considered a Fourier Series? (Wondering)

So do we find the coefficients of the Fourier series

$$f \sim \frac{a_0}{2}+ \sum_{k=1}^{\infty} ( a_k \cos(kx)+ b_k \sin(kx)) $$

and from this we find an orthogonal system? How can we do it? (Thinking)
 
evinda said:
So do we find the coefficients of the Fourier series

$$f \sim \frac{a_0}{2}+ \sum_{k=1}^{\infty} ( a_k \cos(kx)+ b_k \sin(kx)) $$

and from this we find an orthogonal system? How can we do it? (Thinking)

First off, we know that the Fourier series is an orthogonal system. (Nerd)

Since each function in the system must fit the boundary conditions, it follows that $a_k=0$.
So we're left with:
$$f(x) = \sum_{k=1}^{\infty} b_k \sin(kx)$$
(Thinking)

That is, the orthogonal system is:
$$\{ x \mapsto \sin(kx) \mid k \in \mathbb Z_{>0} \}$$
(Mmm)
 
I like Serena said:
First off, we know that the Fourier series is an orthogonal system. (Nerd)

Since each function in the system must fit the boundary conditions, it follows that $a_k=0$.
So we're left with:
$$f(x) = \sum_{k=1}^{\infty} b_k \sin(kx)$$
(Thinking)

That is, the orthogonal system is:
$$\{ x \mapsto \sin(kx) \mid k \in \mathbb Z_{>0} \}$$
(Mmm)

So the complete orthogonal system is the set of the eigenfunctions, right? (Thinking)
 
evinda said:
So the complete orthogonal system is the set of the eigenfunctions, right? (Thinking)

Which eigenfunctions? :confused:
 
I like Serena said:
Which eigenfunctions? :confused:

Oh, this holds only if we are given an initial value problem, right? (Thinking)

So if we are given a function and boundary conditions, do we find the Fourier series of the function and apply the boundary conditions and the orthogonal complete system will consist of the functions $1$ / $\sin kx$ / $\cos kx$ that will remain? (Thinking)
 
evinda said:
Oh, this holds only if we are given an initial value problem, right? (Thinking)

So if we are given a function and boundary conditions, do we find the Fourier series of the function and apply the boundary conditions and the orthogonal complete system will consist of the functions $1$ / $\sin kx$ / $\cos kx$ that will remain? (Thinking)

Basically, yes. (Smile)
 

Similar threads

  • · Replies 19 ·
Replies
19
Views
4K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K