Finding Concentration of a Standard Solution using % purity ?

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SUMMARY

The concentration of a standard Fe2+ solution can be calculated using the purity of the solution and the dilution factors involved. Given 0.1964 g of Fe solution with a purity of 99.7%, the initial concentration is 785.6 mg/L. After diluting 10 mL of this solution to 100 mL, the concentration is calculated as 78.56 ppm. However, to account for the purity, the effective concentration of Fe in the diluted solution is 78.56 ppm multiplied by 0.997, resulting in approximately 78.3 ppm of Fe.

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  • Understanding of ppm (parts per million) calculations
  • Knowledge of solution dilution techniques
  • Familiarity with purity percentage calculations
  • Basic chemistry concepts related to solutions and concentrations
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nerdy_hottie
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Homework Statement



I need to know the concentration in ppm of a standard Fe2+ solution. (diluted)
Here is the data I have.
I have 0.1964 g of Fe solution
the purity is 99.7%

The original solution was the above # of g in 250ml water.
10ml of this was then pipetted into a 100ml volumetric flask and diluted.
I have to find the concentration in ppm of this diluted solution using the info from the starting solution.

Homework Equations



Don't think there are any. Just need logic to figure it out, of which I am limited in.

The Attempt at a Solution



196.4mg/0.250L
=785.6 mg/L
*(10ml/100ml)
=78.56 ppm

This is what I have, but I don't think it's right because 78.56 ppm is not in the range of the spectrometer we used. Also, I didn't use the 99.7% purity anywhere.

Thanks.
 
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nerdy_hottie said:

Homework Statement



I need to know the concentration in ppm of a standard Fe2+ solution. (diluted)
Here is the data I have.
I have 0.1964 g of Fe solution
the purity is 99.7%

The original solution was the above # of g in 250ml water.
10ml of this was then pipetted into a 100ml volumetric flask and diluted.
I have to find the concentration in ppm of this diluted solution using the info from the starting solution.

Homework Equations



Don't think there are any. Just need logic to figure it out, of which I am limited in.

The Attempt at a Solution



196.4mg/0.250L
=785.6 mg/L
*(10ml/100ml)
=78.56 ppm

This is what I have, but I don't think it's right because 78.56 ppm is not in the range of the spectrometer we used. Also, I didn't use the 99.7% purity anywhere.

Thanks.

Actually mg/ml is ppm - work it out.

Then you'll have the ppm of the stuff you put in the flask.

But only 99.7% of the stuff you put there is the Fe you are interested in.
So how many ppm is that?

Simples.

Assuming you have reported the question entirely because I am a bit puzzled about what ppm of "Fe" means, (you didn't weigh out iron filings, does your source give some convention?)
 
Last edited:

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