Finding Constant Acceleration of Train: Liz's Homework Solution

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SUMMARY

The discussion focuses on calculating the constant acceleration of a train based on the time it takes for two cars, each 8.60 m long, to pass a stationary observer. Liz initially calculated the acceleration as 0.8 m/s² using the change in velocity formula, but the correct answer is 1.6 m/s² as per the textbook. The discrepancy arises from the misunderstanding that the formula v = s/t applies to constant velocity, which is not the case here. The correct approach involves setting up two equations to eliminate initial velocity and solve for acceleration.

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atypical
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Homework Statement


Liz rushes down onto a subway platform to find her train already
departing. She stops and watches the cars go by. Each
car is 8.60 m long. The first moves past her in 1.50 s and the
second in 1.10 s. Find the constant acceleration of the train.


Homework Equations


change in velocity=a(t)


The Attempt at a Solution


My answer is different from the book. I found the velocity of each cart given the length and time to pass. From there I took the difference of the two velocities to get my change in velocity.
Then, from the equation i found the total time from both cars to pass then divided to solve for a.

change in velocity=a(t)
therefore: 2.11m/s=a(1.5s+1.1s)
a=0.8m/s^2
Book is getting 1.6m/s^2
...so I am off by a product of 2?
 
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hi atypical! :smile:

(try using the X2 icon just above the Reply box :wink:)
atypical said:
I found the velocity of each cart given the length and time to pass.

nooo … v = s/t only works for constant velocity …

call the initial velocity v, and get two equations for a and v, from which you can eliminate v to find a :smile:
 

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