Finding constant related to random variable

AI Thread Summary
The discussion centers on the calculation of the constant 'a' in the equation Var(Y) = a² . Var(X), where a = ±0.8. The key point is that while both values of a yield the correct mean and variance, a = -0.8 is rejected because it implies a reversal of scores, which is not appropriate for scaling. Participants express concern about the implications of negative scores on exam results, emphasizing that scaling should only stretch or shrink values rather than invert them. The conversation highlights the importance of maintaining positive adjusted scores for clarity and fairness in grading. Ultimately, the consensus is that a should be limited to 0.8 to ensure meaningful results.
songoku
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Homework Statement
Exam marks, X, have mean 70 and standard deviation 8.7. The marks need to be scaled using the formula Y = aX + b so that the scaled marks, Y, have mean 55 and standard deviation 6.96. Find the values of a and b
Relevant Equations
E(aX + b) = a.E(X) + b

Var(aX + b) = a^2 Var (X)
Var (Y) = a2 . Var (X)
(6.96)2 = a2 . (8.7)2
a = ± 0.8

But the answer key states that the value of a is only 0.8

Why a = -0.8 is rejected? Thanks
 
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songoku said:
Why a = -0.8 is rejected?
Why do you think?
 
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PeroK said:
Why do you think?
In my opinion, there are two possible pairs of a and b so a = -0.8 is possible
 
songoku said:
In my opinion, there are two possible pairs of a and b so a = -0.8 is possible
What do you want the mean to be?
 
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You are correct in saying that the -0.8 would give the correct mean and variance, but the term "scaled" is assumed to imply that the values of X are just shifted and stretched/shrunk -- not reversed.
 
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songoku said:
Why a = -0.8 is rejected?
I would be very angry if my raw score (X) on the exam was 70, but my adjusted score wound up being -56.
 
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Mark44 said:
I would be very angry if my raw score (X) on the exam was 70, but my adjusted score wound up being -56.
The proposed formula is ##Y = -0.8X + 111##. Your score of##70## would, indeed, scale to the average of ##55##. But a score of ##80## would scale to ##47##.
 
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PeroK said:
What do you want the mean to be?
For a = -0.8 and b = 111, the mean for Y is 55

Mark44 said:
I would be very angry if my raw score (X) on the exam was 70, but my adjusted score wound up being -56.
Well, I won't because my peers' scores will also be negative :biggrin:

Besides, there is still value of b to make the scaled mark positive

FactChecker said:
You are correct in saying that the -0.8 would give the correct mean and variance, but the term "scaled" is assumed to imply that the values of X are just shifted and stretched/shrunk -- not reversed.
I understand the assumption

Edit: I just saw post #7. That is indeed does not make sense

Thank you for all the help and explanation PeroK, FactChecker, Mark44
 
And the first one now will later be last ...
 
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