MHB Finding Distance with Constant Speed: Solving for m and b

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SUMMARY

The discussion focuses on deriving the equation of distance in the form d = mt + b for John walking in front of a motion sensor. Given the data points d(1) = 2.5 m and d(3) = 4 m, the slope (m) is calculated as 0.75 m/s. The y-intercept (b) is determined to be 1.75 m. The equation representing John's distance from the sensor over time is d = 0.75t + 1.75, allowing for the prediction that John will be 5.25 m from the sensor after 5 seconds.

PREREQUISITES
  • Understanding of linear equations and slope-intercept form
  • Basic knowledge of distance, speed, and time relationships
  • Familiarity with algebraic manipulation to solve equations
  • Concept of motion sensors and their applications
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  • Study linear equations and their applications in real-world scenarios
  • Learn about motion sensors and their functionality in tracking movement
  • Explore the concept of speed and its calculation in physics
  • Investigate the use of distance-time graphs for visualizing motion
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Students in physics or mathematics, educators teaching linear equations, and anyone interested in understanding motion and distance calculations.

Abdullah Qureshi
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John is walking at a constant speed in front of a motion sensor. After 1 s, she is 2.5m from the sensor, 2 s later, she is 4 m from the sensor.
a) Find an equation of in the form d=mt+b
b) Determine the slope and d intercept and explain what they mean
c) How far will John be from the sensor 5s after he begins walking?
 
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distance from the sensor is a function of time in seconds

$d(1) = 2.5 \, m$
$d(1+2) = d(3) = 4 \, m$

slope, $m = \dfrac{\Delta d}{\Delta t} \, m/s$

see what you can do from here ...
 
Equivalently, since you are told that d= mt+ b, when t= 1, d= 2.5, so 2.5= m+ b and when m= 3, d= 4 so 4= 3m+ b.

Solve the two equations, m+ b= 2.5 and 3m+ b= 4, for m and b. I suggest you subtract the first equation from the second to eliminate b.
 

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