Finding energy eigenvalues with perturbation

Click For Summary
To find the energy eigenvalues for two spin-1 particles in a strong magnetic field, start with the Hamiltonian H0 = -B(S1 + S2) and use the basis |m1, m2>, where m can be 1, 0, or -1. The eigenstates |m1, m2> are eigenstates of the Sz operators, which simplifies the calculation of energies. After determining the eigenvalues from H0, introduce the perturbation H1 = -J(S1)_z(S2)_z to find the new energy levels. Apply the perturbation operator to the states |m1, m2> to obtain the perturbed eigenvalues.
boudreaux
Messages
9
Reaction score
0
Homework Statement
There are two spin-1 particles $$S_1,S_2$$
Relevant Equations
$$S_1^2 = S_2^2 = 1(1+1)\hbar^2 = 2\hbar^2$$

there's a strong magnetic field in the Z direction so

$$H_0 = -B*(S_1 +S_2)$$ (all z components here)

I need to fin the eigen-energies and eigenstates of this hamiltonian. Then add a small perturbation

$$H_1 = -J S_1 S_2$$ (still z components) and find the energy levels again.
I know the basis I should use is |m_1,m_2> and that each m can be 1,0,-1 but how do I get the eigenvalues from this?
 
Physics news on Phys.org
boudreaux said:
Homework Statement:: There are two spin-1 particles $$S_1,S_2$$
Relevant Equations:: $$S_1^2 = S_2^2 = 1(1+1)\hbar^2 = 2\hbar^2$$

there's a strong magnetic field in the Z direction so

$$H_0 = -B*(S_1 +S_2)$$ (all z components here)

I need to fin the eigen-energies and eigenstates of this hamiltonian. Then add a small perturbation

$$H_1 = -J S_1 S_2$$ (still z components) and find the energy levels again.

I know the basis I should use is |m_1,m_2> and that each m can be 1,0,-1 but how do I get the eigenvalues from this?
You really mean ## H_1 = - J (S_1)_z (S_2)_z## and not ##- J \vec{S_1} \cdot \vec{S_2}##, right?
Then to get the energies, just apply that operator to all the states ##| m_1 m_2 \rangle##. These are eigenstates of the ##S_z## operators.
 

Similar threads

Replies
46
Views
2K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
5
Views
3K
  • · Replies 17 ·
Replies
17
Views
2K
Replies
17
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K