Finding energy from Inertia and RPM

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Discussion Overview

The discussion revolves around the calculation of energy in motor and gear systems, specifically focusing on the conversion of angular velocity from RPM to radians per second to ensure the energy is expressed in joules. The context includes technical explanations related to physics and engineering principles.

Discussion Character

  • Technical explanation

Main Points Raised

  • Mike inquires about the conversion factor needed to express energy in joules when using inertia and angular velocity in his model.
  • One participant suggests converting RPM to radians per second, providing the conversion formula: 1 RPM = 2*pi/60 rad/s.
  • Another participant confirms the understanding that energy can be calculated using the formula E = 1/2 J * omega^2, with omega being the angular velocity in radians per second.

Areas of Agreement / Disagreement

Participants generally agree on the need to convert angular velocity to radians per second for the energy calculation, and the discussion appears to be resolved regarding this specific conversion.

Contextual Notes

None.

Who May Find This Useful

Individuals working on motor and gear system modeling, particularly those using SPICE or similar simulation tools.

Mike_In_Plano
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Hello,

I'm working on a generalized model for motor / gear systems in SPICE and came across something I don't understand:

Given that the inertia, J, is in kg m^2
and my base unit for angular velocity, w, is kRPM
and the basic equation for energy is E = 1/2 J * w^2

How or what is the conversion factor such that I get joules as my unit of energy?

I feel really silly on this one, I can only claim memory loss...

Thanks in advance,

Mike
 
Engineering news on Phys.org
If you convert RPM to radians/second, it's a done deal. 1 RPM = 2*pi radians/min. = 2*pi/60 rad/s

1 joule = 1 N-m = 1 kg-m^2/s^2
 
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To be certain, let me read back what I think I understand -

To get energy, I convert my angular velocity to radians per second and use this as omega in:

E=1/2 omega^2 J

Correct?
 
Yes.
 

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