1. Plot f(x)=5+ln(-2x+3), and its inverse. 2. I know the inverse of ln(x) is exp(1)^(x)., and to find the inverse of a function, solve for x then swap the x and y. 3. y=5+ln(-2x+3) y-5=ln(-2x+3) exp(1)^(y-5)=(-2x+3) (-1/2)*[exp(1)^(y-5)-3]=x y=(-1/2)*[exp(1)^(x-5)-3] However when I plot these functions using maple, I notice that they are definately not inverse... :( what am i doing wrong?