Finding kth term of a sequence

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SUMMARY

The discussion centers on finding the 100th term of the sequence defined by the series \( U_k = 2 - \frac{1}{n} \). The user seeks to determine \( U_{100} \), the limit of \( U_k \) as \( k \) approaches infinity, and the sum of the series from \( k=1 \) to infinity. The closed form of the sum is confirmed as \( 2 - \frac{1}{n} \), leading to the conclusion that the series converges to 2 as \( n \) approaches infinity.

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Homework Statement


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It's (sigma) from k (possibly n?)=1 to +infinity of [tex]U_{k}[/tex] = 2 - (1/n)

I'm asked to find:

[tex]U_{100}[/tex]

limit as k goes to infinity of [tex]U_{k}[/tex]

and sigma from k=1 to inf. of [tex]U_{k}[/tex]

Homework Equations


If I'm not mistaken, 2 - 1/n is the closed for for the sum, right? I'm just not sure where to go from there...


The Attempt at a Solution


None. :o(
 

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Is the series [itex]\sum_{k=1}^\infty(2-1/n)[/itex]? Or is it [itex]\sum_{k=1}^\infty U_k[/itex] = 2-1/n ?
 
the latter. Thanks!
 

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