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Finding kth term of a sequence

  1. Nov 19, 2007 #1
    1. The problem statement, all variables and given/known data
    See picture

    It's (sigma) from k (possibly n?)=1 to +infinity of [tex]U_{k}[/tex] = 2 - (1/n)

    I'm asked to find:


    limit as k goes to infinity of [tex]U_{k}[/tex]

    and sigma from k=1 to inf. of [tex]U_{k}[/tex]

    2. Relevant equations
    If I'm not mistaken, 2 - 1/n is the closed for for the sum, right? I'm just not sure where to go from there...

    3. The attempt at a solution
    None. :eek:(

    Attached Files:

    Last edited: Nov 19, 2007
  2. jcsd
  3. Nov 19, 2007 #2


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    Is the series [itex]\sum_{k=1}^\infty(2-1/n)[/itex]? Or is it [itex]\sum_{k=1}^\infty U_k[/itex] = 2-1/n ?
  4. Nov 19, 2007 #3
    the latter. Thanks!!
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