Finding Magnetic Moment from Pull Force

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SUMMARY

The discussion focuses on determining the appropriate magnet with a magnetic dipole strength of 0.3 A*m² for an undergraduate project. The magnetic dipole strength is calculated using the formula μ = IA for a current loop and μ = MV for a magnet with magnetization M and volume V. High-quality magnets typically have a magnetization M ranging from 1.0 T to 1.5 T, indicating that a magnet with the required dipole strength would need a volume of approximately 0.2 m³, resulting in a weight of about 1 ton. This raises concerns about the practicality of sourcing such a large magnet.

PREREQUISITES
  • Understanding of magnetic dipole moment calculations
  • Familiarity with magnetization concepts and units
  • Knowledge of the relationship between pull force and magnetic properties
  • Basic principles of magnetism and magnetic fields
NEXT STEPS
  • Research the specifications of magnets from manufacturers that list magnetization values
  • Explore methods for calculating the required volume and weight of magnets based on dipole strength
  • Investigate alternative magnet configurations that may achieve the desired dipole strength with smaller sizes
  • Learn about the practical applications and limitations of large magnets in engineering projects
USEFUL FOR

Students in physics or engineering, researchers in magnetism, and professionals involved in sourcing or designing magnetic systems will benefit from this discussion.

Matt Klosterman
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For an undergraduate project, I need a magnet with a magnetic dipole strength of 0.3 A*m^2. However, all distributors I can find only list their magnets in terms of "pull force" which appears to be defined as the force between a magnet and a steel plate. How do I find a magnet with the dipole I require? Thanks!
 
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If I interpret it correctly, the dipole strength for a magnetic dipole current loop is given by ## \mu=IA ##. For a magnet with magnetization (per unit volume) ## M ##, and volume ## V ## , this also gives a dipole strength of ## \mu=MV ##. Magnetization ## M ## has the same units as ## B ##, since ## B=\mu_o H+M ##. Manufacturers will sometimes list the magnetization ## M ##, and something around ## 1.0 \, T<M<1.5 \, T ## is reasonably common for a high quality magnet. This means the volume of this magnet is going to need to be ## V \approx .2 \, m^3 ##. Perhaps I have misinterpreted something, because this magnet would be quite large, and might weigh about 1 ton.
 

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