Finding magnitude and direction of net force from acceleration vector

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ersc13
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help...The Vector Nature of Newton's Seond Law of Motion

A 350-kg sailboat has an acceleration of 0.62m/s2 at an angle of 64 degress north of east. Find the magnitude and direction of the net force that acts on the sailboat.

I have f=ma to find the force.
F=350(0.62)
F=217N

Then I'm not really sure about the magnitude and direction.
 
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I believe you have to decompose the vector. You have to find [tex]F_{x}[/tex] and [tex]F_{y}[/tex] using the relationships [tex]F_{x} = F\cos\theta, F_{y} = F\sin\theta[/tex]. You are already given the net force.
 
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