Finding Probability in Genetics Experiment: Vermillion Eyes or Miniature Wings?

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SUMMARY

The discussion focuses on calculating the probability of Drosophila fruit flies exhibiting either vermillion eyes or miniature wings based on observed offspring traits. The correct formula for calculating the probability of either event occurring is P(A or B) = P(A) + P(B) - P(A and B), which accounts for overlapping probabilities. The final probability of having either trait is determined to be 8/15, derived from the total counts of flies with each trait and their intersection. The clarification provided by HallsOfIvy emphasizes the importance of understanding how to avoid double counting in probability calculations.

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  • Understanding of basic probability concepts, including independent and dependent events.
  • Familiarity with genetic terminology related to Drosophila traits.
  • Knowledge of how to interpret frequency tables in genetics.
  • Ability to perform basic arithmetic operations with fractions.
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  • Study the principles of probability theory, focusing on the addition and multiplication rules.
  • Learn about conditional probability and its applications in genetics.
  • Explore the concept of overlapping events in probability using Venn diagrams.
  • Review genetic inheritance patterns in Drosophila, particularly regarding eye color and wing size traits.
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Students and educators in genetics, biostatisticians, and anyone interested in applying probability theory to biological experiments.

meowmix
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I suck at probability. I can't think of ways of understanding any problems that involve probability. Here's the problem I'm currently stuck on:

In a genetics experiment, the researcher mated two Drosophila fruit flies and observed the traits of 300 offspring. The results are shown in the table.
Code:
                WING SIZE
EYE COLOR       Normal    Miniature
Normal          140       6
Vermillion      3         151
What is the probability that the fly has either vermillion eyes or miniature wings, or both?

So the first thing I did was make it a little easier for me to understand by rewriting the table in terms of frequency:
Code:
                WING SIZE
EYE COLOR       Normal    Miniature
Normal          4/15      1/50
Vermillion      1/100     151/300

Now I've thought of a method for going about solving the problem but it doesn't work. Isn't it correct that P(A or B) = P(A) + P(B)? So I figured that the answer would be P(VermillionEyes or MiniatureWings or Both) = P(VermillionEyes) + P(MiniatureWings) + P(Both). That would be 154/300 + 157/300 + 151/300. BUT THIS IS OBVIOUSLY WRONG SINCE IT GOES PAST 300/300!

How do I do this? Why is the P(A or B) = P(A) + P(B) thing not working?
 
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A total of 3+ 151= 154 flies have vermilion eyes (now that I would like to see!) and another 6 flies have minature wings so 154+ 6= 160 flies have "either vermillion eyes or miniature wings, out of 300. The probability of that is 160/300= 16/30= 8/15.

Another way to do that is to say the in order not to have "vermilion eyes or miniature wings or both" a fly must have both normal wings and normal eyes. There are 140 such flies so the probability of that is 140/300= 14/30= 7/15. The probability that that is not true is 1- 7/15= (15-7)/15= 8/15 again.

Your mistake is in saying "(VermillionEyes or MiniatureWings or Both) = P(VermillionEyes) + P(MiniatureWings) + P(Both)"

The correct formula is (VermillionEyes or MiniatureWings or Both) = P(VermillionEyes) + P(MiniatureWings) - P(Both). Do you see the minus sign? The reason is that "vermilion eyes" includes "minature wings" and "miniature wings" includes "vermilion eyes". P(Vermilion eyes) and P(MinatureWings) includes both twice. You need to subtract one of them, not add it in again!
 
Thanks HallsOfIvy your explanation was very helpful and clear.
 
dude, u don't suck at all, because u understood it right away when others explained it to u , a bit more practice and u will be fine! =]
 

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