Finding radius of nucleus from semi-empirical mass formula?

[Collisionman]

Homework Statement

The nuclei ^{41}_{21}Sc and ^{41}_{20}Ca are said to be a pair of mirror nuclei. If the binding energy of ^{41}_{21}Sc and ^{41}_{20}Ca is 343.143 MeV and 350.420 MeV, respectively, estimate the radii of the two nuclei with the aid of the Semi-Empirical Mass Formula.

Homework Equations

1. Semi-Empirical Mass Formula: M_{Z,A} = Zm_{p} + Zm_{e}+ \left(A-Z\right)m_{n} -a_{volume}A + a_{surface}A^{\frac{2}{3}}+ a_{coulomb}\frac{Z\left(Z-1\right)}{A^{\frac{1}{3}}}+ a_{asymmetry}\frac{\left(A-2Z\right)^{2}}{A} + \delta
2. Binding Energy: E_{b} = a_{volume}A - a_{surface}A^{\frac{2}{3}}- a_{coulomb}\frac{Z\left(Z-1\right)}{A^{\frac{1}{3}}}- a_{asymmetry}\frac{\left(A-2Z\right)^{2}}{A} - \delta
3. Radius of a nucleus: R=R_{0}A^{\frac{1}{3}}

The Attempt at a Solution

I don't know exactly where to start with this question. I'm not quite sure how to relate the nuclear radius to the SEMF.

Anyway hints/help would be greatly appreciated.

Thanks!

 

[Collisionman]

I'm bumping this question up.

Any help greatly appreciated.

Thanks.