Finding Relations for Coefficients of Polynomial p(x)=0 to Get Real Roots

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This discussion focuses on determining the relationships between coefficients of polynomial equations to ensure that the equation p(x) = 0 has only real roots. For a quadratic equation, the condition p² ≥ 4q (discriminant condition) is established. The conversation extends to sixth-degree polynomials, clarifying that such equations have seven coefficients, not five, and emphasizes that the nature of the roots depends on how these coefficients relate to a single parameter, r. The complexity of ensuring all roots are real increases with the degree of the polynomial and the interdependencies of the coefficients.

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Kadmax
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I'd like to know how to find relations between coefficients of a polynomial p(x) so that equation p(x) = 0 has only real roots.

For example I have quadratic equation:

x[tex]^{2}[/tex]+px+q = 0

then the Discriminant must be >= 0 so p[tex]^{2}[/tex] >= 4q

But I need to find it for equations of higher power of x (like 6), without having the formula for exact solutions - I know it's not possible to solve polynomial equations of order 6 and more.

It may be complicated if there are too many coefficients (there are 5 in 6th order pol.), but they just all depend just on one constant r, so it is like a5 = 2r, a4 = r[tex]^{2}[/tex], a3 = 1/r, and so on, and I need to know for which values of r the equation has only real roots.
 
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It may be complicated if there are too many coefficients (there are 5 in 6th order pol.), but they just all depend just on one constant r, so it is like a5 = 2r, a4 = r, a3 = 1/r, and so on, and I need to know for which values of r the equation has only real roots.
First you had better clear up some misconceptions. In the first place, a 6[/sup]th[/sup] degree (not "order") equation would have 7 coefficients (or 6 if you always take the leading coefficient to be 1 and ignore it), not 5. In general, an nth degree equation has n+1 coefficients, not n-1. Again, you could always divide the equation by the leading coefficient and just use the other n.
Secondly, any set of number can be written as functions of one parameter. How many real roots an equation has would depend upon how each coefficient depends on r and that might be very complicated. Even in the very simple case [itex]x^3+ bx^2+ cx+ d[/itex] whether there are non-real roots would depend upon whether the local min and max are on opposite sides of the x-axis- and that alone can be complicated.
 
i don't know about all real roots ,but i can tell you that for all complex roots
in equation of n th degree whose first coefficient is 1
second ceofficient sqaure<2*third coefficient
and if it is = then all the roots are 0
 

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