- #1

Eagle's Wings

- 17

- 1

## Homework Statement

A 10.0-μF capacitor is charged by a 10.0-V battery through a resistance

*R*. The capacitor reaches a potential difference of 4.00 V at the instant 3.00 seconds after charging begins

1.) Find

*R*

2.) Find the current at t=3.00 seconds after charging begins.

## Homework Equations

i=[itex]\frac{dq}{dt}[/itex]=-[itex]\frac{CV_{ab}}{RC}[/itex]

*e*[itex]^{-t/RC}[/itex]

## The Attempt at a Solution

so obviously I know how to find current but I need to find resistance and I cannot use R=V/I because it is non-ohmic! what do I do?