Finding Spectral Slope in dB/Octave for Hydrophone Data

  • Thread starter Thread starter Clmz
  • Start date Start date
  • Tags Tags
    Data Slope
AI Thread Summary
To find the spectral slope in dB/octave from hydrophone data, calculate the difference in power spectral density (PSD) between two points and divide by the number of octaves between those frequencies. A straight line approximation can be drawn over the frequency range of interest, extending over an octave to read the change in dB. It's important to use grid lines on a log plot to accurately measure frequency doubling, as this ensures consistency across the analysis. Consider smoothing the data to reduce noise while preserving significant spectral peaks. Accurate calculation and representation of frequency and dB changes are essential for reliable spectral slope determination.
Clmz
Messages
3
Reaction score
0

Homework Statement


I have some registration of sound gathered by hydrophone. Next I have created a power spectral density (dB re 1 Pa^2/Hz) vs frequency plot (semilog in matlab). And now I want to find spectral slope in dB/octave (one octave is log2(f2/f1).
I suppose that I should calculate the difference between two PSD points (max and min) and then divide this value by amount of octaves estimated based on the mentioned formula?
Could you if I'm right? Or mby there should use some different formula?

Homework Equations

The Attempt at a Solution

 
Physics news on Phys.org
Semilog...and your horizontal axis is f or log(f/fo)?

One actave is a doubling in frequency. So if linear f can you draw a straight line approximation to any region of interest, then extend that line over an exact octave and read the change in dB.

Drawing by hand has inherent noise-averaging, in comparison with a two points reliance which does not.
 
Here is an example
https://i.imgsafe.org/b3c770eb73.png
 
Last edited by a moderator:
Are you looking for a fixed dB/oct figure? If so, you will be looking for a straight line best fit to this.
 
Ok, so for that I must count the difference value of dB i.e. from 1 Hz - 1.5 Hz and then calculate the amount of decades from taken frequencies?
 
Clmz said:
Ok, so for that I must count the difference value of dB i.e. from 1 Hz - 1.5 Hz and then calculate the amount of decades from taken frequencies?
Why do you mention "decade" when you are interested in per "octave"? Note that 1.5 Hz is difficult to read, it's definitely not midway between grid lines on a log plot.

There is a grid line at 1 Hz, the next grid line adjacent to that is 2 Hz, so why not use that for your double frequency? If you take a plastic ruler and measure this horizontal distance between these 2 grid lines, then everywhere and anywhere along the horizontal axis this same distance (in mm) represents a doubling in frequency. (Try it on the 2 Hz, 3 Hz, 4 Hz, and 5 Hz grid lines to demonstrate this is true.)

Is this noise on the recording, and you want to smooth it before doing calculations? If there are spectral peaks that you want to preserve, then I guess you'll want to exclude them from your smoothing.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Correct statement about a reservoir with an outlet pipe'
The answer to this question is statements (ii) and (iv) are correct. (i) This is FALSE because the speed of water in the tap is greater than speed at the water surface (ii) I don't even understand this statement. What does the "seal" part have to do with water flowing out? Won't the water still flow out through the tap until the tank is empty whether the reservoir is sealed or not? (iii) In my opinion, this statement would be correct. Increasing the gravitational potential energy of the...
Thread 'A bead-mass oscillatory system problem'
I can't figure out how to find the velocity of the particle at 37 degrees. Basically the bead moves with velocity towards right let's call it v1. The particle moves with some velocity v2. In frame of the bead, the particle is performing circular motion. So v of particle wrt bead would be perpendicular to the string. But how would I find the velocity of particle in ground frame? I tried using vectors to figure it out and the angle is coming out to be extremely long. One equation is by work...
Back
Top