Finding Speed using Doppler Shift

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SUMMARY

The discussion focuses on calculating the speed of a star moving relative to Earth using the Doppler Shift formula. The observed frequency of light from the star is 6.1 x 1014 Hz, while the original frequency is 6.0 x 1014 Hz. The calculation reveals that the star is moving away from Earth at a speed of approximately 4,918,032.787 m/s. The confusion arises from the interpretation of the Doppler Shift equation, specifically regarding the sign of the source's speed.

PREREQUISITES
  • Doppler Shift formula for light: f = f0(v + vo)/(v - vs)
  • Understanding of frequency and wave speed in physics
  • Basic algebra for solving equations
  • Concept of relative motion in astrophysics
NEXT STEPS
  • Study the derivation of the Doppler Shift formula for light
  • Learn about the implications of redshift and blueshift in astronomy
  • Explore the effects of relativistic speeds on frequency measurements
  • Investigate other applications of the Doppler Effect in different wave phenomena
USEFUL FOR

Astronomy students, physics enthusiasts, and anyone interested in understanding the motion of celestial bodies relative to Earth.

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Homework Statement

Light with a frequency of 6.1(1014) Hz is measured from a star known to produce light with a frequency of 6.0(1014). How fast is the star moving toward or away from earth?

Homework Equations


f = f0(v + vo)/(v-vs.

f=observed frequency
f0 = original frequency
v=wave speed
vo = wave of observer
vs=wave of source

The Attempt at a Solution



6.1(1014) = 6.0(1014)(3.0x108 + 0)/(3.0x108 + x)

-> (3.0x108 + x) = 6.0(1014)(3.0x108 + 0)/6.1(1014)

-> x = ( 6/6.1 x (3.0(108) ) - 3.0x108

-> -4918032.787 m/s
Moving away at 4918032.787 m/s

I feel that I'm doing it wrong since shouldn't it be moving toward Earth since the frequency observed is higher?
 
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Your equation was: f = f0(v + vo)/(v-vs)
where vs is the speed towards the observer which gives that higher f.

You changed it, for some reason, and used +vs
which, to still be correct, means your vs is now the negative of its speed towards the observer.

You calculated this to be -4918032.787 m/s,
so take the negative of that and you have the speed towards the observer. :smile:

I haven't checked your arithmetic.
 

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