Finding Tension of a string tied to a wall

[DERC511]

In the figure we see two blocks connected by a string and tied to a wall, with θ = 33°. The mass of the lower block is m = 0.9 kg; the mass of the upper block is 4.0 kg. Find the tension in the string that is tied to the wall.
-I have the forces of Block A as Tension, Normal Force, and Gravity (mg). From my calculations I have that Tension equals 0 (which I don't think is correct) and the Normal Force being equal to 39.2.
- For Block B I have the forces as Tension and Gravity, which gives me the Tension being equal to 8.82
- Finally,I separated the tension of the rope on the wall to the x and y components with X: Tcos33 and Y: Tsin33
- We can assume this is all in static equilibrium. Any advice on mistakes or how to proceed with this problem is much appreciated!

 

[billy_joule]

Look at the just the rope join.

There are three forces acting, let's call them T_A to the left, T_B downward, and T_W to the right, Θ degrees above horizontal.

Using ∑F_x = ∑F_y = 0 you can find T_W from theta and T _B using trig, you don't need to know anything about T_A.

 

[DERC511]

Look at the just the rope join.

There are three forces acting, let's call them T_A to the left, T_B downward, and T_W to the right, Θ degrees above horizontal.

Using ∑F_x = ∑F_y = 0 you can find T_W from theta and T _B using trig, you don't need to know anything about T_A.

Thank you for the reply. So you're saying that I can't calculate T_B By equating the Weight of the block to it?

 

[billy_joule]

Thank you for the reply. So you're saying that I can't calculate T_B By equating the Weight of the block to it?

If it's in static equilibrium then the weight of block A has no effect on T_A and is only given to confuse or challenge you, or maybe it's required for a later question.