Finding Terminal Velocity given Mass and magnitude

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Homework Help Overview

The discussion revolves around determining the terminal velocity of a skydiver experiencing a drag force as a function of velocity. The problem involves concepts from mechanics, specifically forces acting on an object in free fall.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to apply Newton's second law and calculate the gravitational force acting on the skydiver. They question whether to equate this force with the drag force to find terminal velocity.

Discussion Status

Participants are engaging in a back-and-forth exploration of the principles involved, with some guidance provided regarding the relationship between forces at terminal velocity. There is a focus on understanding the reasoning behind setting the forces equal.

Contextual Notes

Participants are navigating the requirement to show attempts at solutions before receiving help, which influences the nature of the discussion.

Matt_h
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I'm in physics 1 in college and reviewing for an up coming exam, ran into this problem and can't seem to figure out how to solve it.

A 70 kg skydiver experiences a drag force as a function of velocity (in m/s), opposite the direction of motion, whose magnitude is given

Fd(v)=0.19v^2

What is the skydiver's terminal velocity?

Any help would be appreciated!
 
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Hi, Matt h. Welcome to PF!

The rules here require you to show some attempt at a solution before receiving help. So, how do you think you could get started on this problem? What physics principles or laws are relevant?
 
Oh, ok

Using F=ma i found out that the force due to gravity is
70kg*9.81m/s^2=686.7N

Would i then just plug this force into the magnitude equation above to find the velocity?

After plugging it in i got 60.1 m/s

Does that sound about right?
 
Yes, that looks very good. Do you see why you should set the magnitudes of the two forces equal to each other?
 
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TSny said:
Yes, that looks very good. Do you see why you should set the magnitudes of the two forces equal to each other?

I'm not sure that i do, do you mind explaining it?
 
Newton's 2nd law: Fnet = ma

For an object moving at terminal velocity, what is the value of the acceleration a?
 
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Acceleration would be 0, right?

or no acceleration?
 
Yes. So,...:smile:
 

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