Finding the Angle Between Two Charged Spheres Using Coulomb's Law

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SUMMARY

The discussion focuses on calculating the angle θ between two charged spheres using Coulomb's Law. Two 5.0 g spheres, charged to +31 nC, repel each other and are suspended from 1.0-m-long threads. The solution involves resolving forces into x and y components, applying the equations Tsin(θ) = F and Tcos(θ) = mg, and utilizing the approximation tan(θ) ≈ θ for small angles. The final formula derived for θ is θ = (9 × 10^9 × (31 × 10^-9)^2 / (5 × 10^-3 × 9.8))^(1/3).

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Homework Statement



The figure shows two 5.0 g spheres suspended from 1.0-m-long threads. The spheres repel each other after being charged to +31 nC. What is the angle θ ?
9fs3gh.jpg



Homework Equations



e16f4b0bf23cd9354b492e3581cf9d0f.png



The Attempt at a Solution



i tried it by writing equation in the x and y component for one of the ball and then i would have two unknowns tension and the radius.

now for sin (theta) = r/1
cos (theta) = sqrt(1-r^2)

so for the columbs force the radius would be 2r.

now i solved for r = 4.4108*10^(-5)

this doesn't make sense, i would get the angle to be 2.53*10^(-3)

but the choice for the angles are :
k1ey61.jpg


Thanks for helping
 
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It T is the tension in the string, then
Tsinθ = F

Tcosθ = mg

tanθ = 9*10^9*(31*10^-9)^2/r^2*5*10^-3*9.8

Since θ is very small, tanθ is nearly equal to θ = r

So r^3 = (θ)^3 = 9*10^9*(31*10^-9)^2/5*10^-3*9.8

Now solve to find θ.
 

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