MHB Finding the Area of Triangle ABQ in Rectangle ABCD with Given Points and Lengths

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To find the area of triangle ABQ within rectangle ABCD, the relevant dimensions are established: AB measures 14 units, CP is 13 units, and DP is 15 units. Point P is located on line segment AB, while point Q is on line segment DP, with line CQ perpendicular to DP at point Q. The area of triangle ABQ can be calculated using the formula for the area of a triangle, which is 0.5 times the base times the height. Given the dimensions and the right angle at Q, the area of triangle ABQ is determined to be 105 square units.
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Rectangle $ABCD$ ,point $P$ on $\overline{AB}$ and point $Q$ on $\overline{DP}$ respectively
given: $\overline{AB}=14,\overline{CP}=13$. and $\overline{DP}=15$, if $\overline{CQ}\perp \overline{DP}$ on $Q$
please find the area of $\triangle ABQ$
 
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Albert said:
Rectangle $ABCD$ ,point $P$ on $\overline{AB}$ and point $Q$ on $\overline{DP}$ respectively
given: $\overline{AB}=14,\overline{CP}=13$. and $\overline{DP}=15$, if $\overline{CQ}\perp \overline{DP}$ on $Q$
please find the area of $\triangle ABQ$
my solution:
 

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Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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