Finding the Area of Triangle ABQ in Rectangle ABCD with Given Points and Lengths

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SUMMARY

The area of triangle ABQ within rectangle ABCD can be calculated using the given dimensions: AB = 14, CP = 13, and DP = 15. Point P lies on line segment AB, while point Q is positioned on line segment DP, with line segment CQ perpendicular to DP at point Q. The area of triangle ABQ is determined to be 84 square units through the formula for the area of a triangle, A = 0.5 * base * height, where the base is AB and the height is the vertical distance from Q to line AB.

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Albert1
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Rectangle $ABCD$ ,point $P$ on $\overline{AB}$ and point $Q$ on $\overline{DP}$ respectively
given: $\overline{AB}=14,\overline{CP}=13$. and $\overline{DP}=15$, if $\overline{CQ}\perp \overline{DP}$ on $Q$
please find the area of $\triangle ABQ$
 
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Albert said:
Rectangle $ABCD$ ,point $P$ on $\overline{AB}$ and point $Q$ on $\overline{DP}$ respectively
given: $\overline{AB}=14,\overline{CP}=13$. and $\overline{DP}=15$, if $\overline{CQ}\perp \overline{DP}$ on $Q$
please find the area of $\triangle ABQ$
my solution:
 

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