MHB Finding the Area of Triangle ABQ in Rectangle ABCD with Given Points and Lengths

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To find the area of triangle ABQ within rectangle ABCD, the relevant dimensions are established: AB measures 14 units, CP is 13 units, and DP is 15 units. Point P is located on line segment AB, while point Q is on line segment DP, with line CQ perpendicular to DP at point Q. The area of triangle ABQ can be calculated using the formula for the area of a triangle, which is 0.5 times the base times the height. Given the dimensions and the right angle at Q, the area of triangle ABQ is determined to be 105 square units.
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Rectangle $ABCD$ ,point $P$ on $\overline{AB}$ and point $Q$ on $\overline{DP}$ respectively
given: $\overline{AB}=14,\overline{CP}=13$. and $\overline{DP}=15$, if $\overline{CQ}\perp \overline{DP}$ on $Q$
please find the area of $\triangle ABQ$
 
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Albert said:
Rectangle $ABCD$ ,point $P$ on $\overline{AB}$ and point $Q$ on $\overline{DP}$ respectively
given: $\overline{AB}=14,\overline{CP}=13$. and $\overline{DP}=15$, if $\overline{CQ}\perp \overline{DP}$ on $Q$
please find the area of $\triangle ABQ$
my solution:
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Thread 'Erroneously finding discrepancy in transpose rule'

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