1. The problem statement, all variables and given/known data Problem 62. Capacitors C1 (4 uF) and C2 (2 uF) are charged as a series combination across a 100 V battery. The two capacitors are disconnected from the battery and from each other. They are then connected positive plate to positive plate, and negative plate to negative plate. Calculate the resulting charge on each capacitor. 2. Relevant equations (Charge) = (voltage) or (potential difference) x (capacitance) (Q)=(V)(C) 3. The attempt at a solution I added both capacitors to get a net capacitance, C12 (1.33 uF). Then I used 100V and 1.33 uF to get the charge, Q12 (133). I though that series capacitors had the same charge, but 133 is not the answer. I don't understand the bit about connecting positive plates to positive plates, what is that?