Aprilshowers Messages 14 Reaction score 0 Thread starter Jul 13, 2005 #1 If f(x) = 3x + 1 and g(x) = (x^2 + 5x)^-1/2 find g(f(x))
Aprilshowers Messages 14 Reaction score 0 Jul 13, 2005 #2 Does this look right? f(x) = 3x + 1 g(b) = (b^2 + 5b)^-1/2 Let b=f(x)=3x+1 Substitute 3x + 1 in for b: g(b)=((3x+1)^2+5* (3x+1))^-.5 =(9x^2+6x+1+15x+5)^-.5 =(9x^2+21x+6)^-.5 g(f(x))= (9x^2+21x+6)^-.5 Please advise
Does this look right? f(x) = 3x + 1 g(b) = (b^2 + 5b)^-1/2 Let b=f(x)=3x+1 Substitute 3x + 1 in for b: g(b)=((3x+1)^2+5* (3x+1))^-.5 =(9x^2+6x+1+15x+5)^-.5 =(9x^2+21x+6)^-.5 g(f(x))= (9x^2+21x+6)^-.5 Please advise
HallsofIvy Science Advisor Homework Helper Messages 42,895 Reaction score 983 Jul 13, 2005 #3 Yes, that's exactly right. To find g(f(x)) you replace the "x" in the formula for g with the formula for f(x).
Yes, that's exactly right. To find g(f(x)) you replace the "x" in the formula for g with the formula for f(x).