Finding the Concentration of H3CO2 in a CO2+H2O reaction.

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SUMMARY

The discussion focuses on calculating the concentration of Carbonic Acid (H2CO3) formed from the reaction of Carbon Dioxide (CO2) and water (H2O) in an equilibrium state. The equilibrium constant (K) is derived from the relationship [H2CO3]/([CO2][H2O]), with a known equilibrium concentration of 0.030 moles/L for CO2. The solubility of CO2 in water is established as 1.45 g/L at 25 degrees Celsius and 100 kPa, impacting ocean chemistry and pH levels. The participant seeks clarification on the pressure conditions affecting CO2 solubility and the calculation of K values for subsequent equilibria involving H2CO3.

PREREQUISITES
  • Understanding of chemical equilibrium concepts
  • Knowledge of molarity and concentration calculations
  • Familiarity with the reaction dynamics of CO2 in aqueous solutions
  • Basic grasp of acid-base chemistry and pH implications
NEXT STEPS
  • Research the calculation of equilibrium constants for weak acids, specifically H2CO3
  • Study the impact of CO2 partial pressure on oceanic pH levels
  • Explore the solubility principles of gases in liquids, focusing on Henry's Law
  • Investigate seawater chemistry and its relation to atmospheric CO2 concentrations
USEFUL FOR

Chemistry students, environmental scientists, oceanographers, and anyone interested in the effects of atmospheric CO2 on marine ecosystems.

miniradman
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1. Find the equlibrium constant if there is 0.030moles/L of Carbon Dioxide going in the forward direction and water is in excess to form Carbonic Acid (H2CO3)



Homework Equations


[products]/[reactants] = K



The Attempt at a Solution


I'm trying to figure out how Carbon Dioxide in the atmosphere will affect the chemistry of the oceans. From my research I've found that CO2(g) = CO2(aq) in water is 1.45 g/L where I deduced a equilbrium of 0.030 moles/L. My next step is where I have to figure out how much Carbonic Acid is made (CO2 + H20 = H2CO3) when I know that the equlibrium for the forward direction is 0.039 L/mol. So:

[H2CO3]/[CO2][H2O]

which based on what I know translates to
[H2CO3]/(0.03)[[H2O] = 0.039L/mol

However, L/mol is not the same as mol/L and I need to find the concentration of [H2CO3] because after that I need to figure out the K values for H2CO3 = H++HCO3
and
HCO3 = H++CO3
equilibriums

*sorry, I do apologize but I'm not sure how to get the "reversible reaction" symbol on the physics forums, so I just used an "=" sign :wink:*

ps. I was read on wikipedia that the solubility of Carbon Dioxide is 1.45g/L at 25 degrees C at 100kpa. The pressure, is that including the rest of the atmosphere? or just the carbon dioxide alone? because I've calculate the partial pressure of the CO2to be 11.6139 pa at sea level.
 
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Should I give anymore detail?
More explanation?
More of my working Out?
was the layout incorrect?
... or do people just don't like me...
avatar_69b051c42d85_128.png
 
There are thick books written on the subject. Just carbonic acid is not enough to analyze anything, although you can be sure increasing partial pressure of CO2 lowers water pH. Google for seawater chemistry.
 
Yes, it's a http://aslo.org/lo/toc/vol_18/issue_6/0897.pdf
 
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