Finding the domain of this function

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To find the domain of the function 1/(sqrt(2x)-1)^2, the denominator must not be zero, which occurs when sqrt(2x) equals 1, leading to x being 1/2. Additionally, since the square root requires its argument to be non-negative, 2x must be greater than or equal to 0, resulting in x being greater than or equal to 0. Therefore, the domain is x ≥ 0, excluding x = 1/2. The discussion highlights the importance of ensuring the denominator is positive to avoid undefined values. Understanding these conditions is crucial for determining the valid inputs for the function.
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Homework Statement


Find the domain of 1/(sqrt(2x)-1)2
Note: the minus one is not included under the square root


Homework Equations


Title


The Attempt at a Solution



So the denominator cannot be zero

so that means that sqrt(2x) cannot equal 1
x cannot be 1/2

letting the denominator be greater than 0 gets me x is greater than 1/2

my calculator says x is equal to or greater than 0 but cannot be 1/2

Where did the equal to greater than 0 part come from?
 
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nothingsus said:

Homework Statement


Find the domain of 1/(sqrt(2x)-1)2
Note: the minus one is not included under the square root


Homework Equations


Title


The Attempt at a Solution



So the denominator cannot be zero

so that means that sqrt(2x) cannot equal 1
x cannot be 1/2

letting the denominator be greater than 0 gets me x is greater than 1/2

my calculator says x is equal to or greater than 0 but cannot be 1/2

Where did the equal to greater than 0 part come from?

From the square root. The argument of a square root can't be negative, so you need 2x ≥ 0.
 
nothingsus said:
...

letting the denominator be greater than 0 gets me x is greater than 1/2
...
Why are you concerned about the denominator being greater than zero?
 
The simplest way is, with the answer provided, plug in x=-1 and x=1/2 and you should know why.
 

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