Finding the domain of this function

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nothingsus
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Homework Statement


Find the domain of 1/(sqrt(2x)-1)2
Note: the minus one is not included under the square root


Homework Equations


Title


The Attempt at a Solution



So the denominator cannot be zero

so that means that sqrt(2x) cannot equal 1
x cannot be 1/2

letting the denominator be greater than 0 gets me x is greater than 1/2

my calculator says x is equal to or greater than 0 but cannot be 1/2

Where did the equal to greater than 0 part come from?
 
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nothingsus said:

Homework Statement


Find the domain of 1/(sqrt(2x)-1)2
Note: the minus one is not included under the square root


Homework Equations


Title


The Attempt at a Solution



So the denominator cannot be zero

so that means that sqrt(2x) cannot equal 1
x cannot be 1/2

letting the denominator be greater than 0 gets me x is greater than 1/2

my calculator says x is equal to or greater than 0 but cannot be 1/2

Where did the equal to greater than 0 part come from?

From the square root. The argument of a square root can't be negative, so you need 2x ≥ 0.
 
The simplest way is, with the answer provided, plug in x=-1 and x=1/2 and you should know why.