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Finding the excess after the reaction is complete (chem 101)

  1. Sep 12, 2010 #1
    When 2.0mL of 1.5M Ammonium Phosphate is mixed with 1.00 mL of 0.75 M Ferrous Acetate.

    The problem itself is in multiple parts.
    I have already found the limited reactant. But i need help finding "the grams of the reactant in excess after the reaction is complete."

    What i have so far...
    Ferrous Acetate is limiting reactant with theoretical yield of of 0.09g.
    Ammonium Phosphate has 0.54g of a theoretical yield.

    3. The attempt at a solution

    I have attempted this multiple times and have been searching the web as to how to do it...no positive results so far.
  2. jcsd
  3. Sep 12, 2010 #2


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    Staff: Mentor

    Write reaction equation.

    How many moles of each reactant?

    How many moles of product?

    How many moles of each reactant was consumed during the reaction?

  4. Sep 12, 2010 #3
    balanced equation:
    2(NH4)3PO4 +3Fe(C2H202)2 -> 6NH4(C2H202) + Fe2(PO4)2

    Im not sure how to obtain the rest of what you are asking.
  5. Sep 12, 2010 #4


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    Staff: Mentor

    I already told you in the other thread. You know volume and concentration - start with concentration definition, solve for number of moles of substance.
  6. Sep 12, 2010 #5
    We have
    3e-3 moles of Ammonium Phosphate and
    7.5e-4 moles of Ferrous Acetate

    How do i find how many moles of the product i have and how many moles are consumed?
  7. Sep 13, 2010 #6


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    Staff: Mentor

    Time to write and use reaction equation. You need to know what are stoichiometric coefficients.

    I think I have already directed you to the page where I explained how to read reaction equation.

  8. Sep 25, 2010 #7
    Yes, thank you.
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