Finding the gyromagnetic ratio of an axially symmetric body

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SUMMARY

The discussion centers on deriving the gyromagnetic ratio (g) for an axially symmetric body using angular momentum (L) and magnetic dipole moment (m). The relationship is established as m = gL, where L is expressed through the moment of inertia (I) and angular velocity (ω). The participant encounters difficulties in conceptualizing the integration of mass density (ρ_m) and charge density (ρ_e) to compute the total current (I) flowing through a differential circular loop. The goal is to simplify the integrals to isolate the factor M/Q, which represents the mass-to-charge ratio.

PREREQUISITES
  • Understanding of angular momentum and its relation to magnetic dipole moment
  • Familiarity with moment of inertia and its calculation for axially symmetric bodies
  • Knowledge of charge density and mass density concepts
  • Proficiency in performing integrals in three-dimensional space
NEXT STEPS
  • Study the derivation of the gyromagnetic ratio for different geometries
  • Learn about the application of integrals in calculating physical properties of symmetric bodies
  • Explore the relationship between angular momentum and magnetic properties in classical mechanics
  • Investigate the implications of mass-to-charge ratios in electromagnetic theory
USEFUL FOR

Students and researchers in physics, particularly those focusing on classical mechanics, electromagnetism, and the study of rotational dynamics in symmetric bodies.

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Homework Statement



So, we can presumably write that m = g L, where L is the angular momentum, g the ratio wanted, and m magnetic dipole moment of an axially symmetric body. Total mass is M, total charge Q, mass density \rho_m(r)=\frac{M}{Q}\rho_e(r), where \rho_e(r) is charge density.

Homework Equations



Moment of inertia can also be written I_\omega=\int \rho_m d^2 d\tau where d is the distance from the axis of symmetry.

The Attempt at a Solution



I guess the dipole moment is in the direction of the axis of the symmetry, as is the angular velocity and it can be written:
m = g I_\omega ω

RHS:
= g ω \hat{z} I_\omega

LHS:
m = I \int d\vec{a}

Here is where I guess I'm having conceptual problems. I is the total current, part of which should be a current flowing through a differential circular loop inside the body, at distance d, that is to say:

I = \int \left| v \right| \rho_e d\tau , where \left|v\right| is the module of radial speed of a differential volume element (at distance d) that can be written: \left|v\right|=\left|\omega\right|\left|r\right|sin\theta= ωd. \int d\vec{a} of a differential loop in question is simply d^2 \pi. So, I am getting:

g ω \int \rho_m d^2 d\tau =ω \int d^3 \pi \frac{M}{Q} \rho_m d\tau

Where did I go wrong, how to find g?
 
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anyone? :( the integrals are supposed to annihilate each other leaving me with a factor ~M/Q
 

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