1. The problem statement, all variables and given/known data A 105 kg acrobat jumps up off a platform at a velocity of 2.50 m/s and lands on a teeter-totter 3.00 m below, where another acrobat is waiting. If the waiting acrobat has a mass of 62.5 kg, how high does she get? 2. Relevant equations KE=(1/2)mv^2 PEg= mgh 3. The attempt at a solution I calculated the PE of the first jumper (I disregarded the 2.50 m/s, it seemed unnecessary, please correct me if this is wrong), and got 3090 J. I then plugged that into another PE=mgh equation for the second person and got 5.04 m. Is this correct?