# Finding the horizontal accerelation using forces

## Homework Statement

Interactive Solution 4.11 offers help in modeling this problem.

Two forces, vector F 1 and vector F 2, act on the 5.00 kg block shown in the drawing. The magnitudes of the forces are F1 = 30.5 N and F2 = 47.5 N. What is the horizontal acceleration (magnitude and direction) of the block?

link to picture (let me know if it works): http://www.webassign.net/CJ/04_11.gif

## Homework Equations

SOHCAHTOA equations
Newton's 2nd law: F=ma

## The Attempt at a Solution

Because F1 is at an angle, I broke it up into its y and x components:

sin(-65)*30.5 = -27.6 N
cos(-65)*30.5=-12.89 N

Since the question only asks for the accerelation in the x direction, I got the following equation:
(-47.5 N+-12.89N)=m*a=5*a

Then I solved for a and got 12.078 m/s^2 in the x direction. But the website of my homework is telling me this is wrong. help?

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LowlyPion
Homework Helper
Since the question only asks for the accerelation in the x direction, I got the following equation:
(-47.5 N+-12.89N)=m*a=5*a

Then I solved for a and got 12.078 N in the x direction. But the website of my homework is telling me this is wrong. help?
Except your drawing shows the direction of the force F1 to be positive x.

This means that the horizontal component of F1 is + and that opposes the direction of F2.

Apparently you have taken the sum where the difference would seem to be the correct approach.

i did that too but the computer is telling me thats the wrong answer as well. is it possible that 65 is the wrong angle to use ?