Finding the mass of earths troposphere

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Discussion Overview

The discussion revolves around calculating the mass of Earth's troposphere using pressure and area, with a focus on the mathematical formulation and unit consistency. Participants explore various approaches and corrections related to the initial calculations presented.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant proposes a formula to calculate the mass of air based on pressure and surface area, leading to a result that seems implausible.
  • Another participant points out that the surface area should not be squared in the calculations, indicating a misunderstanding of area dimensions.
  • There is a discussion about the correct interpretation of pressure and its relationship to force and area, with emphasis on the importance of unit consistency in calculations.
  • Some participants argue that ignoring units can lead to incorrect results, highlighting the necessity of maintaining dimensional analysis throughout computations.
  • One participant expresses confusion about the relevance of units in the formulas, prompting further clarification from others.

Areas of Agreement / Disagreement

Participants generally agree on the importance of unit consistency and the correct application of formulas, but there is disagreement regarding the initial approach to calculating the mass of the troposphere and the interpretation of area in the context of pressure calculations.

Contextual Notes

Limitations include potential misunderstandings of dimensional analysis and the implications of unit conversions, which remain unresolved in the discussion.

zeromodz
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I was wondering if I could find the mass of all the air in the local 9.8 g range. This is what I came up with.

P = F / A^2
Ma = PA^2
M = PA^2 / a
M = P(4πR^2)^2 / a
M = P(16π^2R^4) / a
M = (101325)(16π^2(6400000^4)) / (9.8)
M = 2.74e37 kgI know that can't be right, but what did I do wrong?
 
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Surface area of Earth = 500 Million km^2 = 500E12m^2
Air pressure, 101kPa = 10tons/m^2
Total mass = 10E3kg/m^2 * 500E12m^2 = 500E15 kg

hint, you have A^2, but area is already m^2
 
There is one more error. [itex]A = 4\pi R^2 \neq (4 \pi R)^2[/itex]
 
mgb_phys said:
Surface area of Earth = 500 Million km^2 = 500E12m^2
Air pressure, 101kPa = 10tons/m^2
Total mass = 10E3kg/m^2 * 500E12m^2 = 500E15 kg

hint, you have A^2, but area is already m^2

Wait, I thought that the units were irrelevant from the formula.

Then why don't we say that?

P = F / L^2, instead of A^2 or LWH = V^3 ?
 
Last edited:
zeromodz said:
Wait, I thought that the units were irrelevant from the formula.
You have force = pressure/area^2 instead of pressure/area, I think you are getting cofused because pressure is N/m^2
 
@aeromodz
He did. When he converted from Pa to tons, he effectively divided by g. It is no technically correct to have the equal sign in that step.

And F = P*A, not P*A^2. That's what mgb_phys means by A already being m^2.

Finally, you never, ever ignore units. Do computations WITH the units, to make sure your answer is correct.

For example, if I follow your computations keeping units in place, I end up with final answer being in units of kg*m^2 instead of just kg, and that tells me there was a mistake.
 
K^2 said:
@aeromodz
He did. When he converted from Pa to tons, he effectively divided by g. It is no technically correct to have the equal sign in that step.

And F = P*A, not P*A^2. That's what mgb_phys means by A already being m^2.

Finally, you never, ever ignore units. Do computations WITH the units, to make sure your answer is correct.

For example, if I follow your computations keeping units in place, I end up with final answer being in units of kg*m^2 instead of just kg, and that tells me there was a mistake.

Okay thank you. I understand now. I just wasn't thinking.
 

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