omzar
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ive been having a hard time with this question and any help would be appreciated.
If the percent yield in the reaction of methyl iodide (CH3I) with water to form methanol (CH3OH) and HI is 50%, how many moles of methyl iodide will be required to prepare 0.1 mole of methanol? (Assume that water is in excess.)
If the percent yield in the reaction of methyl iodide (CH3I) with water to form methanol (CH3OH) and HI is 50%, how many moles of methyl iodide will be required to prepare 0.1 mole of methanol? (Assume that water is in excess.)